What is the derivative of y=(2x^3+7)^2 ?

The derivative of y=(2x^3+7)^2 is 12x^2(2x^3+7)

What is the first derivative of y=(2x^3+7)^2 ?

The first derivative of y=(2x^3+7)^2 is 12x^2(2x^3+7)

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derivative of

y = (2 x^{3} + 7)^{2}

12 x^{2} (2 x^{3} + 7)

Solution steps

\frac{d}{d x} ((2 x^{3} + 7)^{2})

Apply the chain rule:

2 (2 x^{3} + 7) \frac{d}{d x} (2 x^{3} + 7)

= 2 (2 x^{3} + 7) \frac{d}{d x} (2 x^{3} + 7)

\frac{d}{d x} (2 x^{3} + 7) = 6 x^{2}

= 2 (2 x^{3} + 7) \cdot 6 x^{2}

Simplify

= 12 x^{2} (2 x^{3} + 7)

(t - 2) e^{t}

x \to 4 - lim (\frac{∣ 4 - x ∣}{x - 4})

x \to 1 lim (3)

y^{^{'}} - 2 x y = 6 x

4 x^{3} + 2 x

What is the derivative of y=(2x^3+7)^2 ?
The derivative of y=(2x^3+7)^2 is 12x^2(2x^3+7)
What is the first derivative of y=(2x^3+7)^2 ?
The first derivative of y=(2x^3+7)^2 is 12x^2(2x^3+7)