What is the solution for y^'=ay-by^3 ?

The solution for y^'=ay-by^3 is y=sqrt(a/(-e^{-2a(t+c_{1)))+b}},y=-sqrt(a/(-e^{-2a(t+c_{1)))+b}}

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y^'=ay-by^3

y^{^{'}} = a y - b y^{3}

y = \frac{a}{- e ^{- 2 a (t + c_{1})} + b}, y = - \frac{a}{- e ^{- 2 a (t + c_{1})} + b}

Solution steps

y^{'} (t) = a y (t) - b y (t)^{3}

Solve Bernoulli ODE:

y = \frac{a}{- e ^{- 2 a (t + c_{1})} + b}, y = - \frac{a}{- e ^{- 2 a (t + c_{1})} + b}

y = \frac{a}{- e ^{- 2 a (t + c_{1})} + b}, y = - \frac{a}{- e ^{- 2 a (t + c_{1})} + b}

x^{3}, x^{\frac{1}{3}}, [0, 2]

\frac{\partial}{\partial x} (\frac{x y ^{2}}{t + 2 z})

x \to 0 lim (cot (x) - \frac{1}{x})

\frac{d}{d x} (\frac{x - 1}{x + 3})

11 (t + 1) \frac{d y}{d t} - 8 y = 24 t, y (0) = 16

What is the solution for y^'=ay-by^3 ?
The solution for y^'=ay-by^3 is y=sqrt(a/(-e^{-2a(t+c_{1)))+b}},y=-sqrt(a/(-e^{-2a(t+c_{1)))+b}}