What is the integral of 2e^{5x+e^{5x}} ?

The integral of 2e^{5x+e^{5x}} is 2/5 e^{e^{5x}}+C

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integral of 2e^{5x+e^{5x}}

\int 2 e^{5 x + e^{5 x}} d x

\frac{2}{5} e^{e^{5 x}} + C

Solution steps

\int 2 e^{5 x + e^{5 x}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int e^{5 x + e^{5 x}} d x

Apply u-substitution

: \int e^{u + e^{u}} \frac{1}{5} d u

= 2 \cdot \int e^{u + e^{u}} \frac{1}{5} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{5} \cdot \int e^{u + e^{u}} d u

Apply u-substitution

: \int e^{v} d v

= 2 \cdot \frac{1}{5} \cdot \int e^{v} d v

Use the common integral:

\int e^{v} d v = e^{v}

= 2 \cdot \frac{1}{5} e^{v}

Substitute back

= 2 \cdot \frac{1}{5} e^{e^{5 x}}

Simplify

2 \cdot \frac{1}{5} e^{e^{5 x}} : \frac{2}{5} e^{e^{5 x}}

= \frac{2}{5} e^{e^{5 x}}

Add a constant to the solution

= \frac{2}{5} e^{e^{5 x}} + C

\int sin (2 π x) d x

\frac{d}{d x} (3 x^{2} - 6 x + 10)

1 - 2 x y^{^{'}} = (4 + y^{2})

g (x) = 5

e^{7 x}

What is the integral of 2e^{5x+e^{5x}} ?
The integral of 2e^{5x+e^{5x}} is 2/5 e^{e^{5x}}+C