What is the derivative of (e^x)/(2x^2) ?

The derivative of (e^x)/(2x^2) is (e^x(x-2))/(2x^3)

What is the first derivative of (e^x)/(2x^2) ?

The first derivative of (e^x)/(2x^2) is (e^x(x-2))/(2x^3)

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derivative of

\frac{e ^{x}}{2 x ^{2}}

\frac{e ^{x} ( x - 2 )}{2 x ^{3}}

Solution steps

\frac{d}{d x} (\frac{e ^{x}}{2 x ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (\frac{e ^{x}}{x ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{1}{2} \cdot \frac{\frac{d}{d x} ( e ^{x} ) x ^{2} - \frac{d}{d x} ( x ^{2} ) e ^{x}}{( x ^{2} ) ^{2}}

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (x^{2}) = 2 x

= \frac{1}{2} \cdot \frac{e ^{x} x ^{2} - 2 x e ^{x}}{( x ^{2} ) ^{2}}

Simplify

\frac{1}{2} \cdot \frac{e ^{x} x ^{2} - 2 x e ^{x}}{( x ^{2} ) ^{2}} : \frac{e ^{x} ( x - 2 )}{2 x ^{3}}

= \frac{e ^{x} ( x - 2 )}{2 x ^{3}}

\frac{d}{d x} (\frac{x}{x - 1})

(x^{5} + 2 x) \cdot (x^{3} + x^{2} + x + 7)

\int e^{- x} \cdot cos (w x) d x

y^{^{''}} + y^{^{'}} + y = 0, y (0) = 1, y^{^{'}} (0) = - 1

\frac{\partial}{\partial x} (ln (x^{4} + y^{3}))

What is the derivative of (e^x)/(2x^2) ?
The derivative of (e^x)/(2x^2) is (e^x(x-2))/(2x^3)
What is the first derivative of (e^x)/(2x^2) ?
The first derivative of (e^x)/(2x^2) is (e^x(x-2))/(2x^3)