What is the tangent of 2/(x-2) ?

The tangent of 2/(x-2) is y=-2/((a_{0)-2)^2}x+(4a_{0}-4)/((a_{0)-2)^2}

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tangent of 2/(x-2)

tangent of

\frac{2}{x - 2}

y = - \frac{2}{( a _{0} - 2 ) ^{2}} x + \frac{4 a _{0} - 4}{( a _{0} - 2 ) ^{2}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{2}{a _{0} - 2})

Find the slope of

y = \frac{2}{x - 2} : \frac{d y}{d x} = - \frac{2}{( x - 2 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{2}{( a _{0} - 2 ) ^{2}}

Find the line with slope m=

- \frac{2}{( a _{0} - 2 ) ^{2}}

and passing through

(a_{0}, \frac{2}{a _{0} - 2}) : y = - \frac{2}{( a _{0} - 2 ) ^{2}} x + \frac{4 a _{0} - 4}{( a _{0} - 2 ) ^{2}}

y = - \frac{2}{( a _{0} - 2 ) ^{2}} x + \frac{4 a _{0} - 4}{( a _{0} - 2 ) ^{2}}

y^{^{'}} + e^{- x} y = e^{e - x}

\int_{0}^{4} x - \frac{1}{2} x d x

f (x) = 4 x - x^{2}, at x = 0

\frac{d}{d x} (1 - cos (\frac{x}{2}))

\frac{d}{d x} (261 e^{0, 5 x} + 27.464)

What is the tangent of 2/(x-2) ?
The tangent of 2/(x-2) is y=-2/((a_{0)-2)^2}x+(4a_{0}-4)/((a_{0)-2)^2}