What is the integral from 0 to pi/4 of sin(4x) ?

The integral from 0 to pi/4 of sin(4x) is 1/2

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integral from 0 to pi/4 of sin(4x)

\int_{0}^{\frac{π}{4}} sin (4 x) d x

\frac{1}{2}

Decimal

0.5

Solution steps

\int_{0}^{\frac{π}{4}} sin (4 x) d x

Apply u-substitution

: \int_{0}^{π} sin (u) \frac{1}{4} d u

= \int_{0}^{π} sin (u) \frac{1}{4} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int_{0}^{π} sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= \frac{1}{4} [- cos (u)]_{0}^{π}

Compute the boundaries:

2

= \frac{1}{4} \cdot 2

Simplify

= \frac{1}{2}

\frac{- 3}{( s - 1 ) ^{2}}

f (x) = \frac{x ^{3}}{3} + 4 x^{2} + 12 x + 19

\int - x cos (x) d x

\frac{\partial}{\partial x} (A e^{- 3 x})

y^{^{''}} - 4 y^{^{'}} + 13 y = 0, y (0) = - 1, y^{^{'}} (0) = - 5

What is the integral from 0 to pi/4 of sin(4x) ?
The integral from 0 to pi/4 of sin(4x) is 1/2