What is the limit as x approaches 1 of [2f(x)+g(x)] ?

The limit as x approaches 1 of [2f(x)+g(x)] is 2f(1)+g(1)

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limit as x approaches 1 of [2f(x)+g(x)]

x \to 1 lim ([2 f (x) + g (x)])

2 f (1) + g (1)

Solution steps

x \to 1 lim (2 f (x) + g (x))

Plug in the value

x = 1

, assuming the function is continuous at this point

= 2 f (1) + g (1)

\frac{\partial}{\partial x} (\frac{e ^{x} + e ^{y}}{2})

y = (\frac{( x + 2 )}{( x - 2 ) ^{2}})

\int \frac{- 1}{( x - 1 ) ^{2}} d x

y^{^{''}} + 6 y^{^{'}} + 9 = e^{4 t}, y (0) = 0, y^{^{'}} (0) = 0

\frac{d y}{d x} = \frac{1 - y ^{2}}{x}

What is the limit as x approaches 1 of [2f(x)+g(x)] ?
The limit as x approaches 1 of [2f(x)+g(x)] is 2f(1)+g(1)