What is the limit as x approaches 0-of sin(2x) ?

The limit as x approaches 0-of sin(2x) is 0

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limit as x approaches 0-of sin(2x)

x \to 0 - lim (sin (2 x))

0

Solution steps

x \to 0 - lim (sin (2 x))

Plug in the value

x = 0

= sin (2 \cdot 0)

Simplify

sin (2 \cdot 0) : 0

= 0

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e^{- y} sin (x) - y^{^{'}} cos^{2} (x) = 0

\frac{d}{d x} (- 0.8 sin (x) + cos (2 x))

What is the limit as x approaches 0-of sin(2x) ?
The limit as x approaches 0-of sin(2x) is 0