What is the tangent of y=4tan(x),\at x= pi/3 ?

The tangent of y=4tan(x),\at x= pi/3 is y=16x+4sqrt(3)-(16pi)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=4tan(x),\at x= pi/3

tangent of

y = 4 tan (x), at x = \frac{π}{3}

y = 16 x + 43 - \frac{16 π}{3}

Solution steps

Find the tangent point:

(\frac{π}{3}, 43)

Find the slope of

y = 4 tan (x) : \frac{d y}{d x} = 4 sec^{2} (x)

Compute the slope of

y = 4 tan (x)

x = \frac{π}{3} : m = 16

Find the line with slope m=

16

and passing through

(\frac{π}{3}, 43) : y = 16 x + 43 - \frac{16 π}{3}

y = 16 x + 43 - \frac{16 π}{3}

\frac{d}{d x} (\frac{h ( x )}{x}) x = 2

f (x) = \frac{1}{1 + x ^{2}}

\int \frac{4 x - 16}{x ^{2} - 8 x + 5} d x

\int \frac{3 y}{y ^{2} + z ^{2}} d y

(x - 1)^{12}

What is the tangent of y=4tan(x),\at x= pi/3 ?
The tangent of y=4tan(x),\at x= pi/3 is y=16x+4sqrt(3)-(16pi)/3