en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

xy^'+(x+1)y=x

Solution

x y^{^{'}} + (x + 1) y = x

Solution

y = 1 - \frac{1}{x} + \frac{c _{1}}{e ^{x} x}

Solution steps

x y^{'} (x) + (x + 1) y = x

Solve linear ODE:

y = 1 - \frac{1}{x} + \frac{c _{1}}{e ^{x} x}

y = 1 - \frac{1}{x} + \frac{c _{1}}{e ^{x} x}

Popular Examples

derivative of f(x)=(2x^2-x+1)*(x^2+2x+3)derivative of

f (x) = (2 x^{2} - x + 1) \cdot (x^{2} + 2 x + 3)

integral of 1/((x-1)(x+4))

\int \frac{1}{( x - 1 ) ( x + 4 )} d x

derivative of x^2*arctan(x)derivative of

x^{2} \cdot arctan (x)

limit as x approaches 0+of 5x^{sin(x)}

x \to 0 + lim (5 x^{s i n (x)})

taylor cos(x) pi/2 taylor

cos (x) \frac{π}{2}

Frequently Asked Questions (FAQ)

What is the solution for xy^'+(x+1)y=x ?
The solution for xy^'+(x+1)y=x is y=1-1/x+(c_{1})/(e^xx)