What is the solution for (2x+ye^{y/x})dx-xe^{y/x}dy=0,y(1)=5 ?

The solution for (2x+ye^{y/x})dx-xe^{y/x}dy=0,y(1)=5 is y=ln(2ln(x)+c_{1})x

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(2x+ye^{y/x})dx-xe^{y/x}dy=0,y(1)=5

(2 x + y e^{\frac{y}{x}}) d x - x e^{\frac{y}{x}} d y = 0, y (1) = 5

y = ln (2 ln (x) + c_{1}) x

Solution steps

(2 x + y e^{\frac{y}{x}}) d x - x e^{\frac{y}{x}} d y = 0

Solve using substitution:

y = ln (2 ln (x) + c_{1}) x

y = ln (2 ln (x) + c_{1}) x

\frac{\partial}{\partial x} ((1 - y) + 10 (x - y^{2})^{2})

x y^{^{'}} + 3 y = x^{2} - 1

\frac{\partial}{\partial x} (\frac{x}{y} + \frac{y}{x})

(x + a) e^{3 x} + b

2 x \frac{d y}{d x} = 1 - y^{2}

What is the solution for (2x+ye^{y/x})dx-xe^{y/x}dy=0,y(1)=5 ?
The solution for (2x+ye^{y/x})dx-xe^{y/x}dy=0,y(1)=5 is y=ln(2ln(x)+c_{1})x