What is the integral from 0 to 1 of (e^x) ?

The integral from 0 to 1 of (e^x) is e-1

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integral from 0 to 1 of (e^x)

\int_{0}^{1} (e^{x}) d x

e - 1

Decimal

1.71828 \dots

Solution steps

\int_{0}^{1} e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= [e^{x}]_{0}^{1}

Compute the boundaries:

e - 1

= e - 1

\int \frac{sin ^{3} ( x )}{cos ( x )} d x

\int_{0}^{1} t e^{- t} d t

\frac{5}{s ( s - 1 )}

x \to 2 lim (\frac{x ^{2} + 3}{x - 2})

\int (1 + 3 x^{2}) ln (2 x) d x

What is the integral from 0 to 1 of (e^x) ?
The integral from 0 to 1 of (e^x) is e-1