What is the tangent of f(x)=12sqrt(x)-2x ?

The tangent of f(x)=12sqrt(x)-2x is y=(6/(sqrt(a_{0))}-2)x+6sqrt(a_{0)}

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tangent of f(x)=12sqrt(x)-2x

tangent of

f (x) = 12 x - 2 x

y = (\frac{6}{a _{0}} - 2) x + 6 a_{0}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 12 a_{0} - 2 a_{0})

Find the slope of

f (x) = 12 x - 2 x : \frac{df ( x )}{d x} = \frac{6}{x} - 2

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{6}{a _{0}} - 2

Find the line with slope m=

\frac{6}{a _{0}} - 2

and passing through

(a_{0}, 12 a_{0} - 2 a_{0}) : y = (\frac{6}{a _{0}} - 2) x + 6 a_{0}

y = (\frac{6}{a _{0}} - 2) x + 6 a_{0}

x \frac{d y}{d x} = 2 y

t^{2} cos (- 2 t)

\int_{0}^{1} \frac{2}{1 + x ^{2}} d x

y^{^{'}} = \frac{1}{e ^{y} - x}

\frac{d}{d x} (2 x + 2 y)

What is the tangent of f(x)=12sqrt(x)-2x ?
The tangent of f(x)=12sqrt(x)-2x is y=(6/(sqrt(a_{0))}-2)x+6sqrt(a_{0)}