What is the tangent of 3x-4x^2 ?

The tangent of 3x-4x^2 is y=(3-8a_{0})x+4a_{0}^2

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tangent of 3x-4x^2

tangent of

3 x - 4 x^{2}

y = (3 - 8 a_{0}) x + 4 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 3 a_{0} - 4 a_{0}^{2})

Find the slope of

y = 3 x - 4 x^{2} : \frac{d y}{d x} = 3 - 8 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 3 - 8 a_{0}

Find the line with slope m=

3 - 8 a_{0}

and passing through

(a_{0}, 3 a_{0} - 4 a_{0}^{2}) : y = (3 - 8 a_{0}) x + 4 a_{0}^{2}

y = (3 - 8 a_{0}) x + 4 a_{0}^{2}

\int (1 - sin^{2} (x)) cos (x) d x

\frac{d}{d x} (\frac{x ^{5} - 5}{x + 1})

\frac{\partial}{\partial x} (2 x^{2} y + sin (x^{4}))

x \to 1 lim (x^{\frac{8}{1 - x}})

\frac{\partial}{\partial x} ((x^{3} + y^{3})^{\frac{1}{3}})

What is the tangent of 3x-4x^2 ?
The tangent of 3x-4x^2 is y=(3-8a_{0})x+4a_{0}^2