What is the derivative of (4x)/(sqrt(x^2+6)) ?

The derivative of (4x)/(sqrt(x^2+6)) is (24)/((x^2+6)sqrt(x^2+6))

What is the first derivative of (4x)/(sqrt(x^2+6)) ?

The first derivative of (4x)/(sqrt(x^2+6)) is (24)/((x^2+6)sqrt(x^2+6))

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derivative of

\frac{4 x}{x ^{2} + 6}

\frac{24}{( x ^{2} + 6 ) x ^{2} + 6}

Solution steps

\frac{d}{d x} (\frac{4 x}{x ^{2} + 6})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (\frac{x}{x ^{2} + 6})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 4 \cdot \frac{\frac{d x}{d x} x ^{2} + 6 - \frac{d}{d x} ( x ^{2} + 6 ) x}{( x ^{2} + 6 ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x^{2} + 6) = \frac{x}{x ^{2} + 6}

= 4 \cdot \frac{1 \cdot x ^{2} + 6 - \frac{x}{x ^{2} + 6} x}{( x ^{2} + 6 ) ^{2}}

Simplify

4 \cdot \frac{1 \cdot x ^{2} + 6 - \frac{x}{x ^{2} + 6} x}{( x ^{2} + 6 ) ^{2}} : \frac{24}{( x ^{2} + 6 ) x ^{2} + 6}

= \frac{24}{( x ^{2} + 6 ) x ^{2} + 6}

\int 9 sin^{2} (x) cos^{3} (x) d x

\frac{\partial}{\partial x} (cos (5 z) e^{3 x + 4 y} \cdot 3)

x \to 1 - lim (x ln (x))

y^{^{'}} - (2 x + 1) y + 3 x (5 x - 2) = 0

\frac{5}{x}, 1

What is the derivative of (4x)/(sqrt(x^2+6)) ?
The derivative of (4x)/(sqrt(x^2+6)) is (24)/((x^2+6)sqrt(x^2+6))
What is the first derivative of (4x)/(sqrt(x^2+6)) ?
The first derivative of (4x)/(sqrt(x^2+6)) is (24)/((x^2+6)sqrt(x^2+6))