What is the integral from 0 to 1 of kx ?

The integral from 0 to 1 of kx is k/2

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integral from 0 to 1 of kx

\int_{0}^{1} k x d x

\frac{k}{2}

Solution steps

\int_{0}^{1} k x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= k \cdot \int_{0}^{1} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{1}

= k [\frac{x ^{2}}{2}]_{0}^{1}

Compute the boundaries:

\frac{1}{2}

= k \frac{1}{2}

Simplify

= \frac{k}{2}

y = cos (x^{2})

\frac{d}{d x} (\frac{- 5 x - 9}{2 x + 8})

2.5 x^{3} - 3 x {2}

y = x^{3} - 9 x

\int - \frac{1}{x} d x