What is the integral of 2x(x^2+3)^5 ?

The integral of 2x(x^2+3)^5 is 1/6 (x^2+3)^6+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 2x(x^2+3)^5

\int 2 x (x^{2} + 3)^{5} d x

\frac{1}{6} (x^{2} + 3)^{6} + C

Solution steps

\int 2 x (x^{2} + 3)^{5} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int x (x^{2} + 3)^{5} d x

Apply u-substitution

: \int \frac{u ^{5}}{2} d u

= 2 \cdot \int \frac{u ^{5}}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{2} \cdot \int u^{5} d u

Apply the Power Rule

: \frac{u ^{6}}{6}

= 2 \cdot \frac{1}{2} \cdot \frac{u ^{6}}{6}

Substitute back

u = x^{2} + 3

= 2 \cdot \frac{1}{2} \cdot \frac{( x ^{2} + 3 ) ^{6}}{6}

Simplify

2 \cdot \frac{1}{2} \cdot \frac{( x ^{2} + 3 ) ^{6}}{6} : \frac{1}{6} (x^{2} + 3)^{6}

= \frac{1}{6} (x^{2} + 3)^{6}

Add a constant to the solution

= \frac{1}{6} (x^{2} + 3)^{6} + C

\frac{\partial}{\partial x} (x^{2} + y^{3})

\frac{d}{d x} (\frac{1 - 2 ln ( x )}{4 x ^{3}})

\frac{d}{d x} (y - \frac{1}{( x + 3 )})

\frac{500}{5 t ^{2} + 10 t + 100}

\int \frac{\frac{1}{x}}{ln ( x ) ln ^{2} ( x ) - 1} d x

What is the integral of 2x(x^2+3)^5 ?
The integral of 2x(x^2+3)^5 is 1/6 (x^2+3)^6+C