What is (\partial)/(\partial x)(((u-v))/(u+v)) ?

The answer to (\partial)/(\partial x)(((u-v))/(u+v)) is 0

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(\partial)/(\partial x)(((u-v))/(u+v))

\frac{\partial}{\partial x} (\frac{( u - v )}{u + v})

0

Solution steps

\frac{\partial}{\partial x} (\frac{( u - v )}{u + v})

Treat

u, v

as constants

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

\int 1 + (x)^{2} d x

\int (x + 2) (x - 6) d x

9 y^{^{''}} - 6 y^{^{'}} + 15 y = 0

\int sin (10 x) cos (7 x) d x

\int (20 + 0.6 x) d x

What is (\partial)/(\partial x)(((u-v))/(u+v)) ?
The answer to (\partial)/(\partial x)(((u-v))/(u+v)) is 0