What is (\partial)/(\partial y)(x^2cos(y)) ?

The answer to (\partial)/(\partial y)(x^2cos(y)) is -x^2sin(y)

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(\partial)/(\partial y)(x^2cos(y))

\frac{\partial}{\partial y} (x^{2} cos (y))

- x^{2} sin (y)

Solution steps

\frac{\partial}{\partial y} (x^{2} cos (y))

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x^{2} \frac{\partial}{\partial y} (cos (y))

Apply the common derivative:

\frac{\partial}{\partial y} (cos (y)) = - sin (y)

= x^{2} (- sin (y))

Simplify

= - x^{2} sin (y)

\int 3 x^{2} - 1 d x

y^{^{''}} - 2 y^{^{'}} - 8 y = 0

\frac{d}{d x} ((\frac{3}{2})^{x} ln (\frac{3}{2}))

\int x^{3} 2 + x^{4} d x

\frac{\partial}{\partial y} (x^{2} + 3 x - 4 x y)

What is (\partial)/(\partial y)(x^2cos(y)) ?
The answer to (\partial)/(\partial y)(x^2cos(y)) is -x^2sin(y)