What is the solution for (dy)/(dt)+1/20 y= 3/2 ,y(0)=0 ?

The solution for (dy)/(dt)+1/20 y= 3/2 ,y(0)=0 is y=-30e^{-t/(20)}+30

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(dy)/(dt)+1/20 y= 3/2 ,y(0)=0

\frac{d y}{d t} + \frac{1}{20} y = \frac{3}{2}, y (0) = 0

y = - 30 e^{- \frac{t}{20}} + 30

Solution steps

\frac{d y}{d t} + \frac{1}{20} y = \frac{3}{2}

Solve separable ODE:

y = - 30 e^{- \frac{t}{20}} + 30

y = - 30 e^{- \frac{t}{20}} + 30

\frac{d}{d t} (t cos (t) - sin (t))

(t^{3})^{^{'}}

\frac{d}{d x} ((\frac{x ^{3} - 1}{x ^{3} + 1})^{8})

f (x) = 1 + sin (x), at x = π

f (x) = x^{3} - 74 x^{2} + 40 x + 27490

What is the solution for (dy)/(dt)+1/20 y= 3/2 ,y(0)=0 ?
The solution for (dy)/(dt)+1/20 y= 3/2 ,y(0)=0 is y=-30e^{-t/(20)}+30