What is the tangent of y=x^3-3x^2+2,(3,2) ?

The tangent of y=x^3-3x^2+2,(3,2) is y=9x-25

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of y=x^3-3x^2+2,(3,2)

tangent of

y = x^{3} - 3 x^{2} + 2, (3, 2)

y = 9 x - 25

Solution steps

Find the slope of

y = x^{3} - 3 x^{2} + 2 : \frac{d y}{d x} = 3 x^{2} - 6 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 9

Find the line with slope m=

9

and passing through

(3, 2) : y = 9 x - 25

y = 9 x - 25

y^{^{''}} + 36 y = 48 sec (6 t)

\frac{\partial}{\partial x} ((2 x y - 3) e^{- x y})

\int x^{5} e^{(x^{6} - 4)} d x

\int \frac{x ^{4}}{2} + cos (x) x d x

\frac{\partial}{\partial x} (\frac{x y}{2})

What is the tangent of y=x^3-3x^2+2,(3,2) ?
The tangent of y=x^3-3x^2+2,(3,2) is y=9x-25