What is the derivative of x^2+x+3 ?

The derivative of x^2+x+3 is 2x+1

What is the first derivative of x^2+x+3 ?

The first derivative of x^2+x+3 is 2x+1

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derivative of

x^{2} + x + 3

2 x + 1

Solution steps

\frac{d}{d x} (x^{2} + x + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d x}{d x} + \frac{d}{d x} (3)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

\frac{d}{d x} (3) = 0

= 2 x + 1 + 0

Simplify

= 2 x + 1

\int \frac{7 - 98 x}{25 - 49 x ^{2}} d x

\frac{t d u}{d t} = t^{2} + 3 u, H (4) = 48

\frac{9}{x ^{4}}

\int tan (\frac{x}{2}) d x

\frac{\partial}{\partial x} (x^{2} + y cos (x y))

What is the derivative of x^2+x+3 ?
The derivative of x^2+x+3 is 2x+1
What is the first derivative of x^2+x+3 ?
The first derivative of x^2+x+3 is 2x+1