What is the tangent of y=(x+2)/(x-2),(3,5) ?

The tangent of y=(x+2)/(x-2),(3,5) is y=-4x+17

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tangent of y=(x+2)/(x-2),(3,5)

tangent of

y = \frac{x + 2}{x - 2}, (3, 5)

y = - 4 x + 17

Solution steps

Find the slope of

y = \frac{x + 2}{x - 2} : \frac{d y}{d x} = - \frac{4}{( x - 2 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 4

Find the line with slope m=

- 4

and passing through

(3, 5) : y = - 4 x + 17

y = - 4 x + 17

\int \frac{8 x ^{3} + 3}{( x ^{2} + 2 ) ^{2}} d x

\frac{\partial}{\partial x} (sin^{2} (m x + n y))

\int 2^{s i n^{2} (\frac{1}{3} x)} sin (\frac{2}{3} x) d x

\frac{1}{x ^{2}}, - 1

\int (\frac{6 - 2 x}{8 - 4 x - 4 x ^{2}}) d x

What is the tangent of y=(x+2)/(x-2),(3,5) ?
The tangent of y=(x+2)/(x-2),(3,5) is y=-4x+17