What is (\partial)/(\partial y)(1-x^2y) ?

The answer to (\partial)/(\partial y)(1-x^2y) is -x^2

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(\partial)/(\partial y)(1-x^2y)

\frac{\partial}{\partial y} (1 - x^{2} y)

- x^{2}

Solution steps

\frac{\partial}{\partial y} (1 - x^{2} y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (1) - \frac{\partial}{\partial y} (x^{2} y)

\frac{\partial}{\partial y} (1) = 0

\frac{\partial}{\partial y} (x^{2} y) = x^{2}

= 0 - x^{2}

Simplify

= - x^{2}

\int \frac{x}{( 1 + x )} d x

\frac{d}{d x} ((4 x - 7)^{2})

\frac{d}{d x} ((cos (x)) d x)

ln (x + 3)

\frac{\partial}{\partial y} (- \frac{x}{x ^{2} + y ^{2}})

What is (\partial)/(\partial y)(1-x^2y) ?
The answer to (\partial)/(\partial y)(1-x^2y) is -x^2