What is the limit as n approaches infinity of \sqrt[n]{0.25}-n/n ?

The limit as n approaches infinity of \sqrt[n]{0.25}-n/n is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as n approaches infinity of \sqrt[n]{0.25}-n/n

n \to \infty lim (n 0.25 - \frac{n}{n})

0

Solution steps

n \to \infty lim (n 0.25 - \frac{n}{n})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= n \to \infty lim (n 0.25) - n \to \infty lim (\frac{n}{n})

n \to \infty lim (n 0.25) = 1

n \to \infty lim (\frac{n}{n}) = 1

= 1 - 1

Simplify

= 0

y = \frac{x ^{2} + 1}{x + 1}

\int_{1}^{6} w w + 3 d w

y^{^{''}} + y^{^{'}} + 4 y = 5 x - 7

\int \frac{7}{5} sin (3 x) cos (\frac{x}{3}) d x

\frac{\partial}{\partial x} (\frac{2 y}{x})

What is the limit as n approaches infinity of \sqrt[n]{0.25}-n/n ?
The limit as n approaches infinity of \sqrt[n]{0.25}-n/n is 0