What is the derivative of sin(2x+3y) ?

The derivative of sin(2x+3y) is cos(2x+3y)(2+3(dy)/(dx))

What is the first derivative of sin(2x+3y) ?

The first derivative of sin(2x+3y) is cos(2x+3y)(2+3(dy)/(dx))

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\frac{d}{d x} (sin (2 x + 3 y))

cos (2 x + 3 y) (2 + 3 \frac{d y}{d x})

Solution steps

\frac{d}{d x} (sin (2 x + 3 y))

Apply the chain rule:

cos (2 x + 3 y) \frac{d}{d x} (2 x + 3 y)

= cos (2 x + 3 y) \frac{d}{d x} (2 x + 3 y)

\frac{d}{d x} (2 x + 3 y) = 2 + 3 \frac{d y}{d x}

= cos (2 x + 3 y) (2 + 3 \frac{d y}{d x})

\frac{\partial}{\partial y} (ln (x^{2} + y))

x^{4} - 2 x^{2}, 2 x^{2}, [0, 2]

f (x) = \frac{8 x}{x + 7}, (2, 1.7777700000000 \dots)

y = 5^{x - 3}, (3, 1)

f (x) = x^{3} - 2 x^{2} + x + 1

What is the derivative of sin(2x+3y) ?
The derivative of sin(2x+3y) is cos(2x+3y)(2+3(dy)/(dx))
What is the first derivative of sin(2x+3y) ?
The first derivative of sin(2x+3y) is cos(2x+3y)(2+3(dy)/(dx))