What is the solution for x^{-2}y^{-5}dx+x^{-3}y^{-4}dy=0 ?

The solution for x^{-2}y^{-5}dx+x^{-3}y^{-4}dy=0 is y=sqrt(-x^2+c_{1)},y=-sqrt(-x^2+c_{1)}

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x^{-2}y^{-5}dx+x^{-3}y^{-4}dy=0

x^{- 2} y^{- 5} d x + x^{- 3} y^{- 4} d y = 0

y = - x^{2} + c_{1}, y = - - x^{2} + c_{1}

Solution steps

x^{- 2} y^{- 5} d x + x^{- 3} y^{- 4} d y = 0

Solve separable ODE:

y = - x^{2} + c_{1}, y = - - x^{2} + c_{1}

y = - x^{2} + c_{1}, y = - - x^{2} + c_{1}

\int \frac{x ^{2}}{1 + x ^{3}} d x

\int 7 e^{5} d x

\int 18 cos (3 x) d x

\int_{0}^{1} x^{2} - x^{4} d x

\frac{16}{( s - 4 ) ^{7}}

What is the solution for x^{-2}y^{-5}dx+x^{-3}y^{-4}dy=0 ?
The solution for x^{-2}y^{-5}dx+x^{-3}y^{-4}dy=0 is y=sqrt(-x^2+c_{1)},y=-sqrt(-x^2+c_{1)}