What is the derivative of (2x+5^3*(3x-1)^4) ?

The derivative of (2x+5^3*(3x-1)^4) is 6(2x+5)^2(3x-1)^4+12(3x-1)^3(2x+5)^3

What is the first derivative of (2x+5^3*(3x-1)^4) ?

The first derivative of (2x+5^3*(3x-1)^4) is 6(2x+5)^2(3x-1)^4+12(3x-1)^3(2x+5)^3

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\frac{d}{d x} ((2 x + 5)^{3} \cdot (3 x - 1)^{4})

6 (2 x + 5)^{2} (3 x - 1)^{4} + 12 (3 x - 1)^{3} (2 x + 5)^{3}

Solution steps

\frac{d}{d x} ((2 x + 5)^{3} (3 x - 1)^{4})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = (2 x + 5)^{3}, g = (3 x - 1)^{4}

= \frac{d}{d x} ((2 x + 5)^{3}) (3 x - 1)^{4} + \frac{d}{d x} ((3 x - 1)^{4}) (2 x + 5)^{3}

\frac{d}{d x} ((2 x + 5)^{3}) = 6 (2 x + 5)^{2}

\frac{d}{d x} ((3 x - 1)^{4}) = 12 (3 x - 1)^{3}

= 6 (2 x + 5)^{2} (3 x - 1)^{4} + 12 (3 x - 1)^{3} (2 x + 5)^{3}

\int (- 2^{3 - 2 x}) d x

\int \frac{y}{x} d x

\frac{\partial}{\partial y} (cos (x) + sin (y))

f (x) = 3 6 x + 8

\frac{d}{d x} (tan^{2} (sin (x)))

What is the derivative of (2x+5^3*(3x-1)^4) ?
The derivative of (2x+5^3*(3x-1)^4) is 6(2x+5)^2(3x-1)^4+12(3x-1)^3(2x+5)^3
What is the first derivative of (2x+5^3*(3x-1)^4) ?
The first derivative of (2x+5^3*(3x-1)^4) is 6(2x+5)^2(3x-1)^4+12(3x-1)^3(2x+5)^3