What is the derivative of f(x)=sqrt(x+7) ?

The derivative of f(x)=sqrt(x+7) is 1/(2sqrt(x+7))

What is the first derivative of f(x)=sqrt(x+7) ?

The first derivative of f(x)=sqrt(x+7) is 1/(2sqrt(x+7))

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derivative of

f (x) = x + 7

\frac{1}{2 x + 7}

Solution steps

\frac{d}{d x} (x + 7)

Apply the chain rule:

\frac{1}{2 x + 7} \frac{d}{d x} (x + 7)

= \frac{1}{2 x + 7} \frac{d}{d x} (x + 7)

\frac{d}{d x} (x + 7) = 1

= \frac{1}{2 x + 7} \cdot 1

Simplify

= \frac{1}{2 x + 7}

x = \frac{( y - 2 ) ^{2}}{3}, y = 8 - x

\frac{d}{d x} ((x^{2} + 2)^{- 5} cos (x))

\frac{d}{d x} (x^{5} - 5 x^{3} - 20 x - 2)

y = x^{2}, (0, 2)

\int cos (x) x^{2} d x

What is the derivative of f(x)=sqrt(x+7) ?
The derivative of f(x)=sqrt(x+7) is 1/(2sqrt(x+7))
What is the first derivative of f(x)=sqrt(x+7) ?
The first derivative of f(x)=sqrt(x+7) is 1/(2sqrt(x+7))