What is the slope of y=(6x)/(x^2+1) ?

The slope of y=(6x)/(x^2+1) is (6(-x^2+1))/((x^2+1)^2)

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slope of y=(6x)/(x^2+1)

slope

y = \frac{6 x}{x ^{2} + 1}

\frac{6 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}}

Solution steps

y = \frac{6 x}{x ^{2} + 1}

In order to find the slope of the function, take the derivative of

\frac{6 x}{x ^{2} + 1}

\frac{d}{d x} (\frac{6 x}{x ^{2} + 1}) = \frac{6 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}}

\frac{6 ( - x ^{2} + 1 )}{( x ^{2} + 1 ) ^{2}}

\int_{- 2}^{2} 1 d x

tan (x^{8})

\int 4 sec^{6} (x) d x

\int \frac{1}{s + 2} d s

(- 2, - 5), (2, - 8)

What is the slope of y=(6x)/(x^2+1) ?
The slope of y=(6x)/(x^2+1) is (6(-x^2+1))/((x^2+1)^2)