What is the sum from n=1 to infinity of (n^7)/(6^n) ?

The sum from n=1 to infinity of (n^7)/(6^n) is converges

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sum from n=1 to infinity of (n^7)/(6^n)

n = 1 \sum \infty \frac{n ^{7}}{6 ^{n}}

converges

Solution steps

n = 1 \sum \infty \frac{n ^{7}}{6 ^{n}}

Apply Series Ratio Test:

converges

= converges

\int \frac{( x ^{2} - 49 )}{x ^{3}} d x

ln (1 - 2 y)

\frac{\partial}{\partial x} (2 x + 2 x y)

(x + 2 y) d x + (2 x + y) d y = 0

\int (x^{2} + 3)^{5} d x

What is the sum from n=1 to infinity of (n^7)/(6^n) ?
The sum from n=1 to infinity of (n^7)/(6^n) is converges