What is inverse oflaplace 1/(x^2) ?

The answer to inverse oflaplace 1/(x^2) is t

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inverse oflaplace 1/(x^2)

inverse laplace

\frac{1}{x ^{2}}

t

Solution steps

L^{- 1} {\frac{1}{x ^{2}}}

Use Inverse Laplace Transform table:

L^{- 1} {\frac{( n ) !}{s ^{n + 1}}} = t^{n}

L^{- 1} {\frac{1}{x ^{2}}} = t

= t

(t + 3) (2 t - 1)^{2}

n = 0 \sum \infty n \cdot (\frac{4}{5})^{n}

y = \frac{529 - 8 x}{7 + 7 x}, (4, 7)

\frac{d}{d x} (\frac{a x ^{2} + b x + 1}{x ^{2} - 6 x + 8})

\frac{d ^{2}}{d x ^{2}} ((3 + 2 x) e^{- 5 x})

What is inverse oflaplace 1/(x^2) ?
The answer to inverse oflaplace 1/(x^2) is t