What is (\partial)/(\partial y)(sin(2x+3y)) ?

The answer to (\partial)/(\partial y)(sin(2x+3y)) is cos(2x+3y)*3

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(\partial)/(\partial y)(sin(2x+3y))

\frac{\partial}{\partial y} (sin (2 x + 3 y))

cos (2 x + 3 y) \cdot 3

Solution steps

\frac{\partial}{\partial y} (sin (2 x + 3 y))

Treat

x

as a constant

Apply the chain rule:

cos (2 x + 3 y) \frac{\partial}{\partial y} (2 x + 3 y)

= cos (2 x + 3 y) \frac{\partial}{\partial y} (2 x + 3 y)

\frac{\partial}{\partial y} (2 x + 3 y) = 3

= cos (2 x + 3 y) \cdot 3

\int (\frac{4}{x} + 4 x) d x

(arctan (x^{2}))^{^{'}}

\int \frac{x}{( x ^{2} - 9 ) ^{2}} d x

f (x) = \frac{5}{x ^{6}}

\frac{\partial}{\partial x} (5 + x ln (x y - 9))

What is (\partial)/(\partial y)(sin(2x+3y)) ?
The answer to (\partial)/(\partial y)(sin(2x+3y)) is cos(2x+3y)*3