What is the derivative of (-sin(x)/(sec(x)tan(x))) ?

The derivative of (-sin(x)/(sec(x)tan(x))) is sin(2x)

What is the first derivative of (-sin(x)/(sec(x)tan(x))) ?

The first derivative of (-sin(x)/(sec(x)tan(x))) is sin(2x)

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\frac{d}{d x} (\frac{- sin ( x )}{sec ( x ) tan ( x )})

sin (2 x)

Solution steps

\frac{d}{d x} (\frac{- sin ( x )}{sec ( x ) tan ( x )})

Simplify

\frac{- sin ( x )}{sec ( x ) tan ( x )} : - cos^{2} (x)

= \frac{d}{d x} (- cos^{2} (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (cos^{2} (x))

Apply the chain rule:

2 cos (x) \frac{d}{d x} (cos (x))

= 2 cos (x) \frac{d}{d x} (cos (x))

\frac{d}{d x} (cos (x)) = - sin (x)

= - 2 cos (x) (- sin (x))

Simplify

- 2 cos (x) (- sin (x)) : sin (2 x)

= sin (2 x)

\frac{y d y + x d x}{2 1 + x y} = 0

\frac{\partial}{\partial x} (4 x^{3} y^{\frac{1}{2}})

\frac{d ^{2}}{d x ^{2}} ((x^{2} + 5)^{6})

x \to - 1 lim (\frac{x ^{2}}{x ^{3} - x})

\frac{\partial}{\partial x} (4 y^{2} x^{3})

What is the derivative of (-sin(x)/(sec(x)tan(x))) ?
The derivative of (-sin(x)/(sec(x)tan(x))) is sin(2x)
What is the first derivative of (-sin(x)/(sec(x)tan(x))) ?
The first derivative of (-sin(x)/(sec(x)tan(x))) is sin(2x)