What is (\partial)/(\partial y)(ln(yz)) ?

The answer to (\partial)/(\partial y)(ln(yz)) is 1/y

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(\partial)/(\partial y)(ln(yz))

\frac{\partial}{\partial y} (ln (yz))

\frac{1}{y}

Solution steps

\frac{\partial}{\partial y} (ln (yz))

Treat

z

as a constant

Apply the chain rule:

\frac{1}{yz} \frac{\partial}{\partial y} (yz)

= \frac{1}{yz} \frac{\partial}{\partial y} (yz)

\frac{\partial}{\partial y} (yz) = z

= \frac{1}{yz} z

Simplify

\frac{1}{yz} z : \frac{1}{y}

= \frac{1}{y}

\int \frac{1}{x - y} d x

\int_{- 1}^{1} (13 - 12 u)^{- 1} d u

x \to - 3 lim (4)

\frac{\partial}{\partial x} (x^{4} + 3^{y} + x^{y})

h \to 0 lim (3 x^{2} - 2 x h + 5 h)

What is (\partial)/(\partial y)(ln(yz)) ?
The answer to (\partial)/(\partial y)(ln(yz)) is 1/y