What is (\partial)/(\partial s)(sin(s^2-t^2)) ?

The answer to (\partial)/(\partial s)(sin(s^2-t^2)) is cos(s^2-t^2)*2s

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(\partial)/(\partial s)(sin(s^2-t^2))

\frac{\partial}{\partial s} (sin (s^{2} - t^{2}))

cos (s^{2} - t^{2}) \cdot 2 s

Solution steps

\frac{\partial}{\partial s} (sin (s^{2} - t^{2}))

Treat

t

as a constant

Apply the chain rule:

cos (s^{2} - t^{2}) \frac{\partial}{\partial s} (s^{2} - t^{2})

= cos (s^{2} - t^{2}) \frac{\partial}{\partial s} (s^{2} - t^{2})

\frac{\partial}{\partial s} (s^{2} - t^{2}) = 2 s

= cos (s^{2} - t^{2}) \cdot 2 s

\frac{d}{d x} (ln (2 x^{4} e^{3 x} (x^{2} + x + 1)^{5}))

\int \frac{3 - x}{3 - x ^{2}} d x

\int_{- 2}^{5} - 2 d x

\int \frac{x - 2}{( x ^{2} + x + 2 ) ( x ^{2} + 2 )} d x

\int_{0}^{4} π (2 x)^{2} d x

What is (\partial)/(\partial s)(sin(s^2-t^2)) ?
The answer to (\partial)/(\partial s)(sin(s^2-t^2)) is cos(s^2-t^2)*2s