What is the limit as x approaches 2 of (x^2+8)(2x-4) ?

The limit as x approaches 2 of (x^2+8)(2x-4) is 0

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limit as x approaches 2 of (x^2+8)(2x-4)

x \to 2 lim ((x^{2} + 8) (2 x - 4))

0

Solution steps

x \to 2 lim ((x^{2} + 8) (2 x - 4))

Plug in the value

x = 2

= (2^{2} + 8) (2 \cdot 2 - 4)

Simplify

= 0

y \to - \infty lim (\frac{2 - y}{7 + 6 y ^{2}})

\frac{\partial}{\partial y} (26 - x^{2} - 4 y^{2})

\int \frac{6 x}{7 - 3 x ^{2}} d x

\int_{0}^{2} (4 - x^{2})^{2} d x

x \to 1 - lim (4)

What is the limit as x approaches 2 of (x^2+8)(2x-4) ?
The limit as x approaches 2 of (x^2+8)(2x-4) is 0