What is (\partial)/(\partial x)(3cos(x)) ?

The answer to (\partial)/(\partial x)(3cos(x)) is -3sin(x)

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(\partial)/(\partial x)(3cos(x))

\frac{\partial}{\partial x} (3 cos (x))

- 3 sin (x)

Solution steps

\frac{\partial}{\partial x} (3 cos (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= 3 (- sin (x))

Simplify

= - 3 sin (x)

f (t) = 4 sec (9) (π t - 2)

\int cos^{4} (2 π x) d x

\int sin (n x) sin (m x) d x

f (x) = \frac{3}{2 3 x + 1}, at x = 8

y^{^{'}} = \frac{y}{x} + \frac{x}{2 ( y + x )}

What is (\partial)/(\partial x)(3cos(x)) ?
The answer to (\partial)/(\partial x)(3cos(x)) is -3sin(x)