What is (\partial ^2)/(\partial y^2)(sin^2(mx+ny)) ?

The answer to (\partial ^2)/(\partial y^2)(sin^2(mx+ny)) is 2n^2cos(2(mx+ny))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial ^2)/(\partial y^2)(sin^2(mx+ny))

\frac{\partial ^{2}}{\partial y ^{2}} (sin^{2} (m x + n y))

2 n^{2} cos (2 (m x + n y))

Solution steps

\frac{\partial ^{2}}{\partial y ^{2}} (sin^{2} (m x + n y))

\frac{\partial}{\partial y} (sin^{2} (m x + n y)) = n sin (2 (m x + n y))

= \frac{\partial}{\partial y} (n sin (2 (m x + n y)))

\frac{\partial}{\partial y} (n sin (2 (m x + n y))) = 2 n^{2} cos (2 (m x + n y))

= 2 n^{2} cos (2 (m x + n y))

\int \frac{x ^{2}}{4 x ^{2} + 9} d x

\frac{d}{d x} ((x + 2)^{2})

3 x^{2}, x^{3}

\frac{\partial}{\partial x} (e^{7 x + 3 y})

\int - x 1 - x^{2} d x

What is (\partial ^2)/(\partial y^2)(sin^2(mx+ny)) ?
The answer to (\partial ^2)/(\partial y^2)(sin^2(mx+ny)) is 2n^2cos(2(mx+ny))