What is the derivative of 1/2*ln(x) ?

The derivative of 1/2*ln(x) is 1/(2x)

What is the first derivative of 1/2*ln(x) ?

The first derivative of 1/2*ln(x) is 1/(2x)

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\frac{d}{d x} (\frac{1}{2} \cdot ln (x))

\frac{1}{2 x}

Solution steps

\frac{d}{d x} (\frac{1}{2} ln (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (ln (x))

Apply the common derivative:

\frac{d}{d x} (ln (x)) = \frac{1}{x}

= \frac{1}{2} \cdot \frac{1}{x}

Simplify

\frac{1}{2} \cdot \frac{1}{x} : \frac{1}{2 x}

= \frac{1}{2 x}

\int r^{2} (\frac{r ^{3}}{9} + 7)^{2} d r

\int \frac{x ^{5}}{( 4 - x ^{6} ) ^{4}} d x

\frac{d}{d x} (\frac{1}{2} (x - 1)^{3} sin (\frac{1}{x - 1}))

f (x) = \frac{x}{x ^{2} + 16}, at x = 0

\int \frac{x ^{2}}{( 15 + 4 x - 4 x ^{2} ) ^{\frac{3}{2}}} d x

What is the derivative of 1/2*ln(x) ?
The derivative of 1/2*ln(x) is 1/(2x)
What is the first derivative of 1/2*ln(x) ?
The first derivative of 1/2*ln(x) is 1/(2x)