What is the limit as x approaches-3 of (1-6x)/(3+x) ?

The limit as x approaches-3 of (1-6x)/(3+x) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

limit as x approaches-3 of (1-6x)/(3+x)

x \to - 3 lim (\frac{1 - 6 x}{3 + x})

diverges

Solution steps

x \to - 3 lim (\frac{1 - 6 x}{3 + x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 3 + lim (\frac{1 - 6 x}{3 + x}) = \infty

x \to - 3 - lim (\frac{1 - 6 x}{3 + x}) = - \infty

= diverges

\int tan (x) l e f t (sec (x))^{2} d x

\int t^{2} sinh (t) d t

\int_{0}^{1} \frac{x ^{2}}{x ^{3} + 1} d x

x \to 0.01 lim (\frac{e ^{x} - 1}{x})

\frac{d}{d x} (\frac{sin ( \frac{1}{x} ) x ^{3}}{ln ( x )})

What is the limit as x approaches-3 of (1-6x)/(3+x) ?
The limit as x approaches-3 of (1-6x)/(3+x) is diverges