What is the solution for 2x^2y(dy)/(dx)+1+2xy^2=0 ?

The solution for 2x^2y(dy)/(dx)+1+2xy^2=0 is y=(sqrt(-x+c_{1)})/x ,y=-(sqrt(-x+c_{1)})/x

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2x^2y(dy)/(dx)+1+2xy^2=0

2 x^{2} y \frac{d y}{d x} + 1 + 2 x y^{2} = 0

y = \frac{- x + c _{1}}{x}, y = - \frac{- x + c _{1}}{x}

Solution steps

2 x^{2} y \frac{d y}{d x} + 1 + 2 x y^{2} = 0

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y = \frac{- x + c _{1}}{x}, y = - \frac{- x + c _{1}}{x}

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What is the solution for 2x^2y(dy)/(dx)+1+2xy^2=0 ?
The solution for 2x^2y(dy)/(dx)+1+2xy^2=0 is y=(sqrt(-x+c_{1)})/x ,y=-(sqrt(-x+c_{1)})/x