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Popular >

d/(dθ)(cos(θ)i+3sin(θ)j)

Solution

\frac{d}{d θ} (cos (θ) i + 3 sin (θ) j)

Solution

- i sin (θ) + 3 j cos (θ)

Solution steps

\frac{d}{d θ} (cos (θ) i + 3 sin (θ) j)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (cos (θ) i) + \frac{d}{d θ} (3 sin (θ) j)

\frac{d}{d θ} (cos (θ) i) = - i sin (θ)

\frac{d}{d θ} (3 sin (θ) j) = 3 j cos (θ)

= - i sin (θ) + 3 j cos (θ)

Graph

Popular Examples

derivative of (e^x/(5x^2+9))

\frac{d}{d x} (\frac{e ^{x}}{5 x ^{2} + 9})

integral of (2x+7)/((x-1)^2(x+1))

\int \frac{2 x + 7}{( x - 1 ) ^{2} ( x + 1 )} d x

integral from 1 to 2 of 18x^24^{x^3}

\int_{1}^{2} 18 x^{2} 4^{x^{3}} d x

integral of (x^2)/(sqrt(x+1))

\int \frac{x ^{2}}{x + 1} d x

limit as x approaches 0-of 1+e^{1/x}

x \to 0 - lim (1 + e^{\frac{1}{x}})

Frequently Asked Questions (FAQ)

What is the d/(dθ)(cos(θ)i+3sin(θ)j) ?
The d/(dθ)(cos(θ)i+3sin(θ)j) is -isin(θ)+3jcos(θ)
What is the first d/(dθ)(cos(θ)i+3sin(θ)j) ?
The first d/(dθ)(cos(θ)i+3sin(θ)j) is -isin(θ)+3jcos(θ)