What is (\partial)/(\partial z)(-z) ?

The answer to (\partial)/(\partial z)(-z) is -1

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(\partial)/(\partial z)(-z)

\frac{\partial}{\partial z} (- z)

- 1

Solution steps

\frac{\partial}{\partial z} (- z)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{\partial}{\partial z} (z)

Apply the common derivative:

\frac{\partial}{\partial z} (z) = 1

= - 1

\int \frac{1}{( x - 2 ) ( x - 3 )} d x

y^{^{'''}} + 3 y^{^{''}} - 16 y^{^{'}} - 48 y = 0

\int_{- 3}^{3} \frac{18}{x ^{2} - 6 x - 72} d x

\frac{\partial}{\partial y} (\frac{2 x}{( 2 x + 3 y ) ^{2}})

f (x) = e^{t}

What is (\partial)/(\partial z)(-z) ?
The answer to (\partial)/(\partial z)(-z) is -1