What is the solution for x^2(dy)/(dx)-2xy=3y^4,y(1)= 1/2 ?

The solution for x^2(dy)/(dx)-2xy=3y^4,y(1)= 1/2 is y=(\sqrt[3]{5}x^2)/(\sqrt[3]{-9x^5+49)}

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x^2(dy)/(dx)-2xy=3y^4,y(1)= 1/2

x^{2} \frac{d y}{d x} - 2 x y = 3 y^{4}, y (1) = \frac{1}{2}

y = \frac{3 5 x ^{2}}{3 - 9 x ^{5} + 49}

Solution steps

x^{2} \frac{d y}{d x} - 2 x y = 3 y^{4}

Solve Bernoulli ODE:

y = \frac{3 5 x ^{2}}{3 - 9 x ^{5} + 49}

y = \frac{3 5 x ^{2}}{3 - 9 x ^{5} + 49}

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What is the solution for x^2(dy)/(dx)-2xy=3y^4,y(1)= 1/2 ?
The solution for x^2(dy)/(dx)-2xy=3y^4,y(1)= 1/2 is y=(\sqrt[3]{5}x^2)/(\sqrt[3]{-9x^5+49)}