What is the integral from 0 to 0.15 of x ?

The integral from 0 to 0.15 of x is 0.01125

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integral from 0 to 0.15 of x

\int_{0}^{0.15} x d x

0.01125

Solution steps

\int_{0}^{0.15} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{0.15}

= [\frac{x ^{2}}{2}]_{0}^{0.15}

Simplify

= [0.5 x^{2}]_{0}^{0.15}

Compute the boundaries:

0.01125

= 0.01125

x \to 0 lim (x^{9} cos (\frac{4}{x}))

\int \frac{1}{x 49 x ^{4} - 4} d x

y^{^{''}} - y^{^{'}} - 2 y = t e^{2 t}

- \frac{1}{9} (x^{- 9} - x^{18})

\int ln (9 x + 1) d x

What is the integral from 0 to 0.15 of x ?
The integral from 0 to 0.15 of x is 0.01125