What is the derivative of 3sqrt(x)+8 ?

The derivative of 3sqrt(x)+8 is 3/(2sqrt(x))

What is the first derivative of 3sqrt(x)+8 ?

The first derivative of 3sqrt(x)+8 is 3/(2sqrt(x))

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\frac{d}{d x} (3 x + 8)

\frac{3}{2 x}

Solution steps

\frac{d}{d x} (3 x + 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x) + \frac{d}{d x} (8)

\frac{d}{d x} (3 x) = \frac{3}{2 x}

\frac{d}{d x} (8) = 0

= \frac{3}{2 x} + 0

Simplify

= \frac{3}{2 x}

t (\frac{d y}{d t}) = 2 t e^{t} - y + 6 t^{2}

\int_{0}^{2 π} sin^{2} (t) d t

\frac{\partial}{\partial x} (25 x^{(\frac{3}{4})} y^{\frac{1}{4}})

y^{^{'}} + \frac{2 ( y - 1 )}{x} = 0

\frac{d}{d x} (2 x + 2 x)

What is the derivative of 3sqrt(x)+8 ?
The derivative of 3sqrt(x)+8 is 3/(2sqrt(x))
What is the first derivative of 3sqrt(x)+8 ?
The first derivative of 3sqrt(x)+8 is 3/(2sqrt(x))