What is the tangent of f(x)=15x-1.86x^2,\at x=a ?

The tangent of f(x)=15x-1.86x^2,\at x=a is y=(15-3.72a)x+1.86a^2

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tangent of f(x)=15x-1.86x^2,\at x=a

tangent of

f (x) = 15 x - 1.86 x^{2}, at x = a

y = (15 - 3.72 a) x + 1.86 a^{2}

Solution steps

Find the tangent point:

(a, 15 a - 1.86 a^{2})

Find the slope of

f (x) = 15 x - 1.86 x^{2} : \frac{df ( x )}{d x} = 15 - 3.72 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 15 - 3.72 a

Find the line with slope m=

15 - 3.72 a

and passing through

(a, 15 a - 1.86 a^{2}) : y = (15 - 3.72 a) x + 1.86 a^{2}

y = (15 - 3.72 a) x + 1.86 a^{2}

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\int - 3 x^{2} - 20 x + 2000 d x

(1 + x^{2}) \frac{d y}{d x} - \frac{4 x ^{3} y}{1 - x ^{2}} = 1

\int 3 x^{2} + 8 x - 9 d x

\frac{\partial}{\partial x} (ln (t + 2 c x))

What is the tangent of f(x)=15x-1.86x^2,\at x=a ?
The tangent of f(x)=15x-1.86x^2,\at x=a is y=(15-3.72a)x+1.86a^2