What is the derivative of f(x)=arccos(4x^2) ?

The derivative of f(x)=arccos(4x^2) is -(8x)/(sqrt(1-16x^4))

What is the first derivative of f(x)=arccos(4x^2) ?

The first derivative of f(x)=arccos(4x^2) is -(8x)/(sqrt(1-16x^4))

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derivative of

f (x) = arccos (4 x^{2})

- \frac{8 x}{1 - 16 x ^{4}}

Solution steps

\frac{d}{d x} (arccos (4 x^{2}))

Apply the chain rule:

- \frac{1}{1 - ( 4 x ^{2} ) ^{2}} \frac{d}{d x} (4 x^{2})

= - \frac{1}{1 - ( 4 x ^{2} ) ^{2}} \frac{d}{d x} (4 x^{2})

\frac{d}{d x} (4 x^{2}) = 8 x

= - \frac{1}{1 - ( 4 x ^{2} ) ^{2}} \cdot 8 x

Simplify

- \frac{1}{1 - ( 4 x ^{2} ) ^{2}} \cdot 8 x : - \frac{8 x}{1 - 16 x ^{4}}

= - \frac{8 x}{1 - 16 x ^{4}}

θ \to 0 lim (\frac{1}{11})

sin^{2} (x)

x \to 0 + lim (\frac{2 ^{x}}{3 ^{x} - 1})

\frac{d}{d x} ((x + 2 x) e^{x})

\int 16 - 5 x^{2} d x

What is the derivative of f(x)=arccos(4x^2) ?
The derivative of f(x)=arccos(4x^2) is -(8x)/(sqrt(1-16x^4))
What is the first derivative of f(x)=arccos(4x^2) ?
The first derivative of f(x)=arccos(4x^2) is -(8x)/(sqrt(1-16x^4))