What is the derivative of (x^2-3e^x) ?

The derivative of (x^2-3e^x) is 2xe^x+e^x(x^2-3)

What is the first derivative of (x^2-3e^x) ?

The first derivative of (x^2-3e^x) is 2xe^x+e^x(x^2-3)

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\frac{d}{d x} ((x^{2} - 3) e^{x})

2 x e^{x} + e^{x} (x^{2} - 3)

Solution steps

\frac{d}{d x} ((x^{2} - 3) e^{x})

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = x^{2} - 3, g = e^{x}

= \frac{d}{d x} (x^{2} - 3) e^{x} + \frac{d}{d x} (e^{x}) (x^{2} - 3)

\frac{d}{d x} (x^{2} - 3) = 2 x

\frac{d}{d x} (e^{x}) = e^{x}

= 2 x e^{x} + e^{x} (x^{2} - 3)

\int \frac{3 x ^{2} + 1}{x ^{5} - x} d x

(0.5) (- 2.4)

y^{^{'}} = 5 y + y^{6}, y (0) = 1

\int_{0}^{x} \frac{1}{t ^{2} + t + 1} d t

x \to 0 lim (sec (2 x))

What is the derivative of (x^2-3e^x) ?
The derivative of (x^2-3e^x) is 2xe^x+e^x(x^2-3)
What is the first derivative of (x^2-3e^x) ?
The first derivative of (x^2-3e^x) is 2xe^x+e^x(x^2-3)